Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM. Pls hep

Answer:   about 35.18Step-by-step explanation:The Law of Sines tells you the relationship between the sides and angles is ...   KM/sin(L) = KL/sin(M) = LM/sin(K)We are given LM and angles K and M. __The sum of angles is 180°, so the remaining angle is ...   ∠K +∠L +∠M = 180°   60° +∠L +45° = 180° . . . . substitute the given angle values   ∠L = 75° . . . . . . . . . . . . . . subtract 105°__Now, we're in a position to find the missing side lengths.   KM = sin(L)/sin(K)·LM = sin(75°)/sin(60°)·12 ≈ 13.38   KL = sin(M)/sin(K)·LM = sin(45°)/sin(60°)·12 ≈ 9.80__The perimeter of ΔKLM is ...   P = KL +KM +LM   P = 9.80 +13.38 +12.00   P = 35.18