MATH SOLVE

2 months ago

Q:
# Course HomeIf a container of liquid contains 60 oz of solution, what is the number of ounces of pure acid if the given solution contains the following acid concentrations?(a) 20% (b) 25% (c) 30% (d) 50%Announcementoz.Assignments(a) The amount of pure acid in 60 oz of 20% acid solution is(Type an integer or a decimal.)(b) The amount of pure acid in 60 oz of 25% acid solution is(Type an integer or a decimal.)oz.Student Gradeboz.(b) The amount of pure acid in 60 oz of 30% acid solution is(Type an integer or a decimal.)Study Planoz.TEXTBOOK(b) The amount of pure acid in 60 oz of 50% acid solution is(Type an integer or a decimal.)Video and ResoiLibraryAccessible ResoPurchase Optioi Enter your answer in each of the answer boxes.OType here to search

Accepted Solution

A:

Answer:(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.(b) The amount of pure acid in 60 oz of 25% acid solution is 15 oz.(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz. Step-by-step explanation:* Lets explain how to solve the problem- The solution is a mixture of two or more substances- A container of liquid contains 60 oz of solution- The solution contains pure acid by different concentrations- (a) 20% (b) 25% (c) 30% (d) 50%- We want to find the number of ounces of the pure acid in each concentration- Assume that the solution is 100% - That means 100% represents 60 oz of solutiona)- The percentage of pure acid is 20%∵ solution ⇒ pure acid 100% 20% 60 The number of ounces- By using cross multiplication∴ The number of ounces = [tex]\frac{60*20}{100}= 12[/tex](a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.b)- The percentage of pure acid is 25%∵ solution ⇒ pure acid 100% 25% 60 The number of ounces- By using cross multiplication∴ The number of ounces = [tex]\frac{60*25}{100}= 15[/tex](b) The amount of pure acid in 60 oz of 25% acid solution is 15oz.c)- The percentage of pure acid is 30%∵ solution ⇒ pure acid 100% 30% 60 The number of ounces- By using cross multiplication∴ The number of ounces = [tex]\frac{60*30}{100}= 18[/tex](c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.d)- The percentage of pure acid is 30%∵ solution ⇒ pure acid 100% 50% 60 The number of ounces- By using cross multiplication∴ The number of ounces = [tex]\frac{60*50}{100}= 30[/tex](d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.