Q:

Find the constant difference for each table of values and use it to describe the data(linear, quadratic,or exponential

Accepted Solution

A:
Answer:   6.  quadratic   7.  linearStep-by-step explanation:6. First differences are ...5 -2 = 36 -5 = 15 -6 = -12 -5 = -3Second differences are ...1 -3 = -2-1 -1 = -2-3 -(-1) = -2These are constant at -2, so the data are quadratic. The data can be described by y = 6-(x-3)^2.__7. The x-values are evenly spaced (though decreasing). For our purpose, we can still look at the first differences of the table values in the order given. First differences are ...8 -4 = 412 -8 = 416 -12 = 420 -16 = 4These are constant at +4, so the data are linear. The data can be described by y = -4x +12.