Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM. Pls hep
Accepted Solution
A:
Answer: about 35.18Step-by-step explanation:The Law of Sines tells you the relationship between the sides and angles is ... KM/sin(L) = KL/sin(M) = LM/sin(K)We are given LM and angles K and M. __The sum of angles is 180°, so the remaining angle is ... ∠K +∠L +∠M = 180° 60° +∠L +45° = 180° . . . . substitute the given angle values ∠L = 75° . . . . . . . . . . . . . . subtract 105°__Now, we're in a position to find the missing side lengths. KM = sin(L)/sin(K)·LM = sin(75°)/sin(60°)·12 ≈ 13.38 KL = sin(M)/sin(K)·LM = sin(45°)/sin(60°)·12 ≈ 9.80__The perimeter of ΔKLM is ... P = KL +KM +LM P = 9.80 +13.38 +12.00 P = 35.18